4(x/7+x^4)+49=4x^4-x/7+1

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Solution for 4(x/7+x^4)+49=4x^4-x/7+1 equation: 


x in (-oo:+oo)

4*(x^4+x/7)+49 = 4*x^4-(x/7)+1 // - 4*x^4-(x/7)+1

4*(x^4+x/7)-(4*x^4)+x/7-1+49 = 0

4*(x^4+x/7)-4*x^4+x/7-1+49 = 0

4*(x^4+1/7*x)-4*x^4+x/7-1+49 = 0

(4*7*(x^4+1/7*x))/7+(-4*7*x^4)/7+x/7+(-1*7)/7+(7*49)/7 = 0

4*7*(x^4+1/7*x)-4*7*x^4+x-1*7+7*49 = 0

4*x+x-7+343 = 0

5*x-7+343 = 0

5*x+336 = 0

(5*x+336)/7 = 0

(5*x+336)/7 = 0 // * 7

5*x+336 = 0

5*x+336 = 0 // - 336

5*x = -336 // : 5

x = -336/5

x = -336/5

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